![algebraic geometry - Stein factorization $X\to B'\to B$ and $k(B')$ is algebraically closed in $k(X)$ - Mathematics Stack Exchange algebraic geometry - Stein factorization $X\to B'\to B$ and $k(B')$ is algebraically closed in $k(X)$ - Mathematics Stack Exchange](https://i.stack.imgur.com/uP7Lv.png)
algebraic geometry - Stein factorization $X\to B'\to B$ and $k(B')$ is algebraically closed in $k(X)$ - Mathematics Stack Exchange
![algebraic geometry - Transcendence degree of the function field of a variety is same as the krull dimension of its arbitry local ring? - Mathematics Stack Exchange algebraic geometry - Transcendence degree of the function field of a variety is same as the krull dimension of its arbitry local ring? - Mathematics Stack Exchange](https://i.stack.imgur.com/CsCNQ.png)
algebraic geometry - Transcendence degree of the function field of a variety is same as the krull dimension of its arbitry local ring? - Mathematics Stack Exchange
I learned in Galois Theory that any field can be algebraically closed, with the proof using Zorn's Lemma. Is the algebraic closure of a finite field recognizable in any sense, like the
![PDF) Diophantine Undecidability of Function Fields of Characteristic Greater than 2, Finitely Generated over Fields Algebraic over a Finite Field | Alexandra Shlapentokh - Academia.edu PDF) Diophantine Undecidability of Function Fields of Characteristic Greater than 2, Finitely Generated over Fields Algebraic over a Finite Field | Alexandra Shlapentokh - Academia.edu](https://0.academia-photos.com/attachment_thumbnails/94495412/mini_magick20221119-1-18qbc0.png?1668844039)
PDF) Diophantine Undecidability of Function Fields of Characteristic Greater than 2, Finitely Generated over Fields Algebraic over a Finite Field | Alexandra Shlapentokh - Academia.edu
![algebraic geometry - Transcendence degree of the function field of a variety is same as the krull dimension of its arbitry local ring? - Mathematics Stack Exchange algebraic geometry - Transcendence degree of the function field of a variety is same as the krull dimension of its arbitry local ring? - Mathematics Stack Exchange](https://i.stack.imgur.com/4VdpM.png)
algebraic geometry - Transcendence degree of the function field of a variety is same as the krull dimension of its arbitry local ring? - Mathematics Stack Exchange
![PDF) Hilbert's Tenth Problem over Function Fields of Positive Characteristic Not Containing the Algebraic Closure of a Finite Field PDF) Hilbert's Tenth Problem over Function Fields of Positive Characteristic Not Containing the Algebraic Closure of a Finite Field](https://i1.rgstatic.net/publication/237145594_Hilbert's_Tenth_Problem_over_Function_Fields_of_Positive_Characteristic_Not_Containing_the_Algebraic_Closure_of_a_Finite_Field/links/57321b5708aea45ee8363ec6/largepreview.png)
PDF) Hilbert's Tenth Problem over Function Fields of Positive Characteristic Not Containing the Algebraic Closure of a Finite Field
![algebraic geometry - Unramified morphism of schemes: why is "finite" put in parentheses in the statement of this proposition - Mathematics Stack Exchange algebraic geometry - Unramified morphism of schemes: why is "finite" put in parentheses in the statement of this proposition - Mathematics Stack Exchange](https://i.stack.imgur.com/NZMfT.png)